An architect is sketching a doorway, the top of which is part of a circle of a radius 50 in. The central angle is 100
How many inches long will the arc be?
\(\bf \textit{arc length}=s=\cfrac{\theta \pi r}{180} \\ \quad \\ r = radius\qquad \theta=\textit{angle in degrees}\)
How would you set it up i am confused
well, what's the given radius? what's the given angle? plug them in
\(\bf \textit{arc length}=s=\cfrac{\theta \pi r}{180} \\ \quad \\ r = radius=50\qquad \theta=\textit{angle in degrees}=100 \\ \quad \\ \textit{arc length}=s=\cfrac{100\cdot \pi \cdot 50}{180}\)
An architect is sketching a doorway, the top of which is part of a circle of a radius 50 in. The central angle is 100 ... 100 what? If you have that unit of measurement correct, then JDoe's suggestion would make more sense.
the general formula for arc length is very simple: s = r*theta, where theta is the central angle. theta must, repeat, must, be in radians.
radius is 50 given angle100
I do not understand could you set it up please?
ok so 100*3.14*50/180=87.2 The answers are \[43\left(\begin{matrix}41 \\ 63\end{matrix}\right)\] \[87\left(\begin{matrix}19 \\ 63\end{matrix}\right)\] \[130\left(\begin{matrix}60 \\ 63\end{matrix}\right)\] 164\[164\left(\begin{matrix}38 \\ 63\end{matrix}\right)\]
s = arc length = (radius) * (central angle, in radians) What is the radius? You'll need to write more than just '50'. what is the central angle? You'll need to write more than just '100.'
In other words: Please always include units of measurement when talking about some measure.
The only measurement the give me is inches
Yes. So then please type in "50 inches" for the radius, not just '50.' I'd bet that if you go back and look at the original problem, you'd see that the central angle is 100 degrees. Why? because 100 radians would be about 5,730 degrees. I'm sure you haven't ever heard of a central angle of 5,730 degrees. So, please type in "100 degrees" for the central angle.
Now, as before, the arc length is s = r * theta. first, convert that 100 degree central angle to radians. Note what JDoe did: He used a conversion factor.
I'll be happy to pick up again where we left off. Hope you won't let this long discussion go to waste. See you again soon?
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