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Chemistry 19 Online
OpenStudy (anonymous):

the percent composition of nitrogen in NH4OH (gram-formula mass = 35 grams/mole) is equal to

OpenStudy (anonymous):

N = 14 g H = 1 g x 5 = 5 O = 16g 35 is total molar mass so 14g/35g x 100 = the percentage.

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