Suppose p varies directly with d, and p = 3 when d = 5. What is the value of d when p = 12? (Points : 4)
@mathbrz
do you know the basic formula for "direct variation"? y = kx p = kd where k is constant. So plug in your values for p and d to determine K now use the original formula with K and solve for d if p is 12
it would be 20?
absolutely correct. Good Job!
Given the function T(z) = z − 8, find T(−2). (Points : 4) 6 10 −10 −6
substitute -2 every time you see z
idk what it would be
\(\bf T({\color{red}{ z}}) = {\color{red}{ z}} − 8\qquad \qquad T({\color{red}{ -2}})={\color{red}{ \square }}-8\)
what do you think?
i figured it out umm how about this If f(x) = |x + 7|, find f(−12). (Points : 1) −5 19 5 −19
same way x = -12 keep in mind your rules of absolute values
-5
eep in mind your rules of absolute values <--- | value inside the bars, always comes out positive once the bars are removed |
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