Question

Check my work please...

Answer 1

is that \[\tan(x) +\frac{ 1 }{ \sin (x) }?\]

Answer 2

\[tanx + \frac{ cosx }{ 1+sinx } = secx\]

Answer 3

okay

Answer 4

\[\frac{ Sinx }{ Cosx }+\frac{ Cosx }{ 1+sinx }\]

Answer 5

go on

Answer 6

\[\frac{ Sinx+Sin ^{2}x+Cos ^{2}x }{ Cosx+CosxSinx }\]

Answer 7

\[\frac{ Sinx+1 }{ Cosx(1+Sinx) } = \frac{ 1 }{ Cosx } = Secx\]

Answer 8

I am not sure if what I did above is legal though?

Answer 9

Which step?

Answer 10

When I get \[\frac{ 1 }{ Cosx }\]

Answer 11

You're worried about that of all things?
XD
sin(x) + 1 and 1 + sin(x) should cancel out, nothing wrong with that :)

Answer 12

if you are not sure, check all the trig list

Answer 13

Thank You @terenzreignz and @celestialdictator, I was trying to justify if it was correct... it was just killing me! :D

Answer 14

http://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf

Answer 15

It does? lol apparently the mathlegend is human after all XD

Answer 16

that is what you use to justify your steps