Question

algebra 2?!?!?

Answer 1

Yes? Depends on the question

Answer 2

Shoot, we didn't get to those yet /:
I really wish I could help :(

Answer 3

$$
\large
\cfrac{x^{1/3}}{x^{1/2}}
$$
Bring the denominator up and add exponents:
$$
\large
x^{1/3}\times x^{-1/2}=x^{1/3 - 1/2}=x^{\cfrac{2-3}{6}}=x^{-1/6}
$$
Make sense so far?

Answer 4

yeah is that the answer?

Answer 5

That is the process for the 1st one. In words, you need to bring the exponents of the variable x to the numerator then simplify by adding exponents.

For the second part...

Answer 6

$$
\Large{
\sqrt[32]{x\times x^2\times x^5}\\
=\left(x\times x^2\times x^5\right)^{1/32}\\
=\left(x^{8}\right)^{1/32}\\
=x^{8/32}\\
=x^{1/4}
}
$$
In words, convert the radical to a power and add the exponents of the variable x.
Next, multiply the power of x with the outside exponent and simplify the resulting power of x.

That's it!

Good luck!!

Answer 7

thank you!!!

Answer 8

Correction to the 1st part:
$$
\large
x^{1/3}\times x^{-1/12}=x^{4/12 - 1/12}=x^{\cfrac{4-3}{12}}=x^{3/12}=x^{1/4}
$$

Notice that Megan and Julie's final result are equal to \(x^{1/4}\). So they are both equivalent.

Answer 9

yw