Question

if y=cosx^2 - sinx^2, find y'

Answer 1

-2sinx-2cosx

Answer 2

\[y'=2\cos x \left( -\sin x \right)-2\sin x \cos x=-4\sin x \cos x=-2\sin 2x\]

Answer 3

Which is squared? The x or the cosine?

Answer 4

x

Answer 5

i mean cos

Answer 6

or y=cos^2x-sin^2x=cos 2x
\[y=\cos 2x,y'=-2\sin 2x\]

Answer 7

Thank you! :)

Answer 8

yw