Question

2 times the square root x -5 = 2

Answer 1

7

Answer 2

\(\Huge\color{blue}{ \sf 2 \sqrt{x-5}=2 }\) divide both sides by 2

\(\Huge\color{blue}{ \sf \sqrt{x-5}=1 }\) square both sides

\(\Huge\color{blue}{ \sf (\sqrt{x-5})^2=(1)^2 }\) (simplify...)

\(\Huge\color{blue}{ \sf x-5=1 }\)

add 5 to both sides \(\Huge\color{blue}{ \sf x-5+5=1 +5}\)

\(\Huge\color{blue}{ \sf x=6 }\)

Answer 3

\(\Huge\color{blue}{ \frak Welcome~~to }\) \(\Huge\color{orangered}{ \frak OPENSTUDY! }\)

Answer 4

why would u divide ?

Answer 5

both sides by 2? To eliminate the square root

Answer 6

to isolate not eliminate (sorry)

Answer 7

\(\large\color{blue}{ \it If~~you~~~are~~not~~clear~~Ask! }\)

Answer 8

so x= 6 so would the solution be not extraneous?

Answer 9

\(\Huge\color{red}{ \sf 2\sqrt{x-5}=2 }\)

\(\Huge\color{red}{ \sf 2\sqrt{\color{royalblue} { 6 }-5}=2 }\)

\(\Huge\color{red}{ \sf 2\sqrt{1}=2 }\)

\(\Huge\color{red}{ \sf 2=2 }\)


SO....... YES OR NO ?

Answer 10

I have to choose one so is it no?

Answer 11

it is yes. because when i plugged it in it worked.

Answer 12

yeah I got wrong but thanks.

Answer 13

WHAT?! you got it wrong?!?!

But that's impossible !

Answer 14

6 is for sure correct, I don't know what they teach in schools, but this I DO know ...
agh I am so mad bro ! How could that be !!!!!!!!!!!!!??????

Answer 15

it probably was the part where it asked whether it was extraneous or not. but, its ok thanks though.