Question

Find the real solutions, if any of each system.

Answer 1

\[y=x^2 \]

Answer 2

\[x^2+y^2=12\]

Answer 3

x^2 + (x^2)^2 = 12 ;
x^2 + x^4 = 12;
x^6 = 12;
x = 2

im pretty sure this is right, sorry im trying.

Answer 4

i like how you worked it out

Answer 5

are you allowed to add to unlike powers like x^2 and x^4?

Answer 6

and that is not correct according to my answer key

Answer 7

\[(\sqrt{3}, 3), (-\sqrt{3},3)\]

Answer 8

work it out step by step

Answer 9

that is the correct answer ^ but i don't know how it is , it is correct from my answer key... so i don't know why @kaseymarie is getting medals.

Answer 10

its ok just let her

Answer 11

she will be happy at least

Answer 12

here....... a medal

Answer 13

I'm stuck at\[x^2+x^4=12\]

Answer 14

thanks for the medal but I want to figure this system out haha, guess no one can

Answer 15

try to do it on a calculator

Answer 16

search it up

Answer 17

that's impossible

Answer 18

SOMEONE HELP HIM!!!

Answer 19

there,....... my work is done...:):):)

Answer 20

\[x^2+y^2=12\]

\[y+y^2=12\]

Answer 21

wow thank you so much! I can't believe I didn't notice that thank you!

Answer 22

wow

Answer 23

@ninjastrike u don't get a medal haha U didn't help me...

Answer 24

haha i dont want your medal.. haha

Answer 25

good

Answer 26

excellent

Answer 27

phenomenal

Answer 28

ok......

Answer 29

well, whatever.... back to work

Answer 30

ok

Answer 31

ya sorry i said i wasnt sure i was just giving what i would have done for the problem to solve it. i didnt say i was right. aand ya i dont deserve a medal @hello1213 sorry.

Answer 32

its fine