Question

I need to balance following equation:

V10O28^-6 + HO^- --> VO4^-3

Answer 1

You want to balance this?

\(\large\sf V_{10}O_{28}^{\ \ \ -6}+OH^-\to VO_4^{\ -3}\)

You need to make sure you have the same amount of vanadium and oxygen atoms on both sides of the arrow. Also you need to add \(\sf H_2O\) on the right to make up for the hydrogen atom on the left. Then you also need to add electrons on the right (since it's done under alkaline conditions (hence the OH- instead of H+) to balance the charges.

Answer 2

Yes, I have tried exactly as you wrote. I will try once again, Thomaster.

Answer 3

Oke, tell me if you can't figure it out :)

Answer 4

Thomaster, I can't figure this out. I tried by multiple the right side by 10 to have the same amount of vanadium on both side. Then I'll have 40 oxygen atoms on right and 29 oxygen on right. I multiplied the hydroxide ion with 11 to have 40 oxygen on both sides. But how do I balance the hydrogen with H2O?

Answer 5

You're on the right way.

\(\large\sf V_{10}O_{28}^{\ \ \ -6}+OH^-\to \color{red}{10}VO_4^{\ -3}+H_2O\)

We now have :
V: 10 -> V: 10
O: 29 -> O: 41
H : 1 -> H: 2

So we only have to change something to the OH on the left and the H2O on the right.
since the H is in a 1:2 ratio, you need to double the coefficient on the left.
So when you make it 4OH, you need to have H2O at 2

Now go on adding coefficient until the equation is balanced.

Answer 6

Thank you very much Thomaster. I understand it now. I have a similar one, which I will try by my own.

I just have a question.
When I get a reaction, where the conditions are not given, like alkaline or acidic. How do I know, if I need to balance that equation according to the alkaline or acidic conditions.

A example, I know that dichromate is predominate in acidic conditions, and chromate is predominate in alkaline conditions.

Are there other compounds, where the following rule is true?

Thanks for your time, Thomaster!