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Chemistry 13 Online
OpenStudy (anonymous):

Calculate the energy in J of 0.32 moles of photons whose frequency is 2.6 x 10^15?

OpenStudy (accessdenied):

Have any ideas so far?

OpenStudy (anonymous):

Convert the moles to photons?

OpenStudy (accessdenied):

That would be a fine starting point. :)

OpenStudy (anonymous):

Then what would I do after that?

OpenStudy (accessdenied):

Well, that action would give us the total number of photons we are looking at. In a sense the energy should then be the energy of one individual photon times how many we have.

OpenStudy (anonymous):

Could you explain how to calculate that please? I am just having some trouble understanding this topic..

OpenStudy (accessdenied):

Well, we are given a frequency. We need to find the energy. Do you recall seeing these two formulas: E = h v h is planck constant, v is frequency <-- we need frequency here... c = w v c is speed of light, w is wavelength, v is frequency <-- this is to convert frequency and wavelength

OpenStudy (anonymous):

Yes

OpenStudy (accessdenied):

So, the procedure is like this: (a) Convert the wavelength 2.6 x 10^15 to frequency (c = w v) (b) Use frequency and Planck constant to find Energy (E = h v = h c/w )

OpenStudy (anonymous):

Ok, thank you!

OpenStudy (accessdenied):

Glad to help! and once you find energy there, don't forget to multiply by the number of photons to get the overall energy.

OpenStudy (anonymous):

Ok, I wont forget

OpenStudy (ipwnbunnies):

The question already provides the frequency. So you can straight find the energy of one photon with the formula AD provided.

OpenStudy (accessdenied):

oh wow, i entirely just imagined this question saying we had wavelength. :x thanks for pointing it out @iPwnBunnies

OpenStudy (accessdenied):

so its actually easier than that, skip (a) because we have frequency E = h v sorry for the mix up!

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