OpenStudy (anonymous):

A logging barge on the Mississippi river travels 24 miles up stream in 3 hours. The return trip takes the barge only 2 hours. Find the rate of chang of the barge in still waters.

3 years ago
OpenStudy (nurali):

Speed is distance divided by time. Going upstream slows you down by the speed of the river \[V _{barge}-V _{river}=\frac{ 24 miles }{ 3hours }=8mph\] Going downstream you go faster: \[V _{barge}+V _{river}=\frac{ 24 miles }{ 2hours }=12mph\] If you add the two equations, Vriver cancels and you get: \[2V _{barge}=20mph\] \[V _{barge}=10mph\]

3 years ago
OpenStudy (anonymous):

thankyou uvu

3 years ago
Similar Questions: