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A logging barge on the Mississippi river travels 24 miles up stream in 3 hours. The return trip takes the barge only 2 hours. Find the rate of chang of the barge in still waters.
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Speed is distance divided by time. Going upstream slows you down by the speed of the river \[V _{barge}-V _{river}=\frac{ 24 miles }{ 3hours }=8mph\] Going downstream you go faster: \[V _{barge}+V _{river}=\frac{ 24 miles }{ 2hours }=12mph\] If you add the two equations, Vriver cancels and you get: \[2V _{barge}=20mph\] \[V _{barge}=10mph\]
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