Tommy flips a coin five times. How many ways can he get four heads and one tail?
A 10 ways B 32 ways C 5 ways
@ganeshie8
can you show me your attempt on solving this problem so I know where to start
I don't know how to do this problem
please help me
like this...
so you can get HHHHT HHHTH HHTHH HTHHH THHHH I will give credit to hoblos as he aswered the same question like this
|dw:1395596062854:dw| so 4 of the spots will be filled with heads and on with tails. how many of the spots could possibly be tails?
1 spot
well, for a particular sequence yes but any of the spots could be tails.
ok
is there a possible for it to be 10 ways
the way to think of this is witth combinations. you have 5 availble spots, choose 1. that gives \[_5C_1 =\left(\begin{matrix}5 \\ 1\end{matrix}\right)=\frac{ 5! }{ (5-1)!\,\,1! }=5\]
ok thank you
well, for 2 tails out of 5 flips you'd get \[_5C_2 = \left(\begin{matrix}5 \\ 2\end{matrix}\right)=\frac{ 5! }{ (5-2)!\,\,2! }=10\]
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