Question

8x^3-27y^3

Answer 1

so what is the question ?
factorize ?

Answer 2

Yea factor the polynomial completely

Answer 3

no i don't think so

Answer 4

No, this can be factored! It's a difference of cubes.

\[a^3 - b^3 = (a-b)(a^2+ab + b^2)\]

Answer 5

\[a^3 = 8x^3\]\[a = \sqrt[3]{8}*\sqrt[3]{x^3} = 2x\]\[b^3=27y^3 \]\[b = \sqrt[3]{27}\sqrt[3]{y^3} = 3y\]

Now fill in the template to get the factoring...

Answer 6

If you haven't seen the difference of cubes formula before:
\[(a-b)(a^2+ab+b^2) = a(a^2+ab+b^2) - b(a^2+ab+b^2)\]\[\qquad = a^3 + a^2b + ab^2 -a^2b - ab^2-b^3\]\[\qquad=a^3 - b^3\]