Question

Given that,
\[\int\limits_{-1}^{4} f(x) dx = 3 \]

find:

\[\int\limits_{-1}^{4} 2f(x) + 1/2 dx \]

Answer 1

Split it into two integrals

Answer 2

hmm, ok. i will try.

Answer 3

\[\int\limits_{-1}^{4} 2f(x) dx \] + \[\int\limits_{-1}^{4} 1/2 dx \]

Answer 4

is it like this?

Answer 5

Yes

Answer 6

the f(x) dx, I must put 3 ?

Answer 7

It's 2f(x)dx

Answer 8

So it's 6

Answer 9

i dont get the answer,

Answer 10

This is not the answer

Answer 11

But \(\Large\displaystyle\int_{-1}^42f(x)dx=2\int_{-1}^4f(x)dx=2\times3=6\)

Answer 12

and then it become 6x ? and other one become 1/2 x

Answer 13

@ganeshie8 can you help me out here ?

Answer 14

\(\large \int\limits_{-1}^{4} 2f(x) + \frac{1}{2} dx\)


\(\large \left(2\int\limits_{-1}^{4} f(x) dx\right) + \left(\int\limits_{-1}^{4} \frac{1}{2} dx\right)\)


\(\large \left(2\times 3\right) + \left(\frac{1}{2} \int\limits_{-1}^{4} 1dx\right)\)


\(\large \left(6\right) + \left(\frac{1}{2} [4--1]\right)\)


\(\large \left(6\right) + \left(\frac{5}{2} \right)\)


\(\large \frac{17}{2} \)

Answer 15

let me knw if somthng doesnt make sense..

Answer 16

let me try first..

Answer 17

okiee

Answer 18

ok, completely understand... :D thank you again. I glad you are around when I need ya.

Answer 19

good to hear :) u wlc !!