Assume the y varies inversely with x and y = -3 when x = 4. Write the indirect variation equation for the relationship.
Start with the general form for inverse variation: y = k/x where k is a constant.
Now, all you need to do is figure out what k is. Since they gave you x and y values, you can substitute them into your formula.
\(\bf \begin{array}{cccllll} \textit{something }&\textit{varies inversely to }&\textit{something else}\\ \quad \\ \textit{something }&=\cfrac{{\color{red}{ \textit{some value }}}}{\textit{something else}}\\ \quad \\ y&=\cfrac{{\color{red}{ n}}}{x} &&\implies y=\cfrac{{\color{red}{ n}}}{x} \end{array} \\ \quad \\ y=-3\qquad x=4\qquad -3=\cfrac{{\color{red}{ n}}}{(4)}\) solve for "n" to find the "constant of variation", then plug it back in the original equation
That actually helped a lot, I haven't tried it. Thanks!
Yes, what jdoe said is correct
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