I need an answer can't figure it out the "cot" is messing me up... find dy/dx y=2cosxcotx

Question

*insert name here* · Answer

Use product rule.

*insert name here* · Answer

$$\LARGE y'=2cosx(cotx)'+cotx(2cosx)'$$

johnweldon1993 · Answer

Hint* Product rule and $$\large \frac{d}{dx} \cot(x) = -\csc^2(x)$$

anonymous · Answer

its not working

anonymous · Answer

i get (2cosx-csc^2x -sinxcotx

anonymous · Answer

write it as y= 2cos^2x/sinx and then use the quotient rule to differentiate

anonymous · Answer

oh so i was on the right path in my notebook writing cot as cos/sin and simplifying before differentiating?

anonymous · Answer

yeah sure if you're more familiar differentiating cos and sin rather than cot since cot happens to mess you up

anonymous · Answer

nah that doesn't work either nevermind ima ask the professor what is the answer to this one though... i'd like to see if i can work it backwards and maybe figure it out that way

anonymous · Answer

Always better to ask a professor than random people anyway :P

anonymous · Answer

true but can you give me the answer

anonymous · Answer

meh, it doesn't matter anyway...ask your professor. Much better for your learning experience