Question

i need help!!

find the exact value of

sin(2cos^-1(7/25))

Answer 1

sin[2sin^-1(7/25) ] = sin A = 336/625

Answer 2

How? lol. I would like to know the steps so i can learn it

Answer 3

sin [ 2 sin^-1(7/25) ]

let 2sin^-1(7/25) = A

sin^-1(7/25) = A/2

sin(A/2) = 7/25

cos(A/2) = √(1 - 49/625) = √576/625 = 24/25

sin A = 2sin(A/2) cos(A/2) = 2(7/25)(24/25)

= 336 /625

sin[2sin^-1(7/25) ] = sin A = 336/625