Check my answers ?
@ganeshie8
Lena is writing statements as shown to prove that if segment ST is parallel to segment RQ, then x = 35.
Statement Reason 1. Segment ST is parallel to segment QR Given 2. Angle QRT is congruent to angle STP Corresponding angles formed by parallel lines and their transversal are congruent. 3. Angle SPT is congruent to angle QPR Reflexive property of angles. 4. Triangle SPT is congruent to triangle QPR Angle-Angle Similarity Postulate 5. ? Corresponding sides of similar triangles are in proportion.
Which equation can she use as statement 5? x:15 = 28:40 28:12 = x:(x + 15 ) x + 15 = 28 + 12 28:40 = x:(x + 15)
do you have any pictures to correspond to your geometry proof? @arilove1d
https://lh3.ggpht.com/S8L3CnNxEjzgbs3KwMgNmMsvj16MY7S-93HGIOuFQunVpUrCdims-u2_E0OniK7KbkfiDw=s120
@Jamierox4ev3r I think its the last one
Go Jamie ~
oh sorry, erm I've been afk. Taking care of a few chores, you can solve this one @tHe_FiZiCx99
Fizi is going to bed X_X fizi has been facing his computer for the past 11 hours ._.
What do you guys think ?
Yes. The last one is correct
Okay Thank you can you help me with a few more
just looking at it, the last one seems correct :) sorry for not being on here consistently! >.<
Its okay :)
A student made the following chart to prove that AB2 + BC2 = AC2.
https://lh5.ggpht.com/-Ec6C9VKTTRFz16rIAk5RHm1GhZtB6mDRpia2RFKuuW5ukyWxDArAZsrdaOd6ufDc1zh=s153
Statement Justification 1. Triangle ABC is similar to triangle BDC 1. Angle ABC = Angle BDC and Angle BCA = Angle BCD 2. BC2 = AC x DC 2. BC ÷ DC = AC ÷ BC because triangle ABC is similar to triangle BDC 3. Triangle ABC is similar to triangle ABD 3. Angle ABC = Angle ADB and Angle BAC = Angle BAD 4. AB2 = AC x AD 4. AB ÷ AD = AB ÷ AC because triangle ABC is similar to triangle ADB 5. AB2 + BC2 = AC x AD + AC x DC = AC (AD + DC) 5. Adding Statement 1 and Statement 2 6. AB2 + BC2 = AC2 6. AD + DC = AC
What is the flaw in the student's proof? Justification 2 should be "BC ÷ DC = BC ÷ AC because triangle ABC is similar to triangle BDC." Justification 4 should be "AB ÷ AD = AC ÷ AB because triangle ABC is similar to triangle ADB." Justification 1 should be "Angle ABC = Angle BCD and Angle BCA = Angle DBC." Justification 3 should be "Angle ABC = Angle BAD and Angle BAC = Angle ABD."
I'm confused on this one
Any idea so far?
no not really
Is statement1 and justification1 correct?
yes
Is statement2 and justification2 correct?
no
Why not?
im not really sure i was looking at the last part of justification 2 and thought it was wrong then realized its right
I dont understand justification 2 and 4
Do you understand why BC ÷ DC = AC ÷ BC?
No
not really :(
|dw:1395813881457:dw|
Do you see why BC/EF = AC/DF ?
Yes now i see it
Just the same thing in justification 2 & 4
I dont see how AC relates to BC and DC
Are you talking about 2 or 4?
2
i think the answers the second one
correct
thank you so the second justification is incorrect
yep
Thank you !
Can you check my answers to the rest of my questions?
1. Lena is writing statements as shown to prove that if segment ST is parallel to segment RQ, then x = 35. Statement Reason 1. Segment ST is parallel to segment QR Given 2. Angle QRT is congruent to angle STP Corresponding angles formed by parallel lines and their transversal are congruent. 3. Angle SPT is congruent to angle QPR Reflexive property of angles. 4. Triangle SPT is congruent to triangle QPR Angle-Angle Similarity Postulate 5. ? Corresponding sides of similar triangles are in proportion. Which equation can she use as statement 5? x:15 = 28:40 28:12 = x:(x + 15 ) x + 15 = 28 + 12 28:40 = x:(x + 15) I got D
2. A student made the following chart to prove that AB2 + BC2 = AC2. Statement Justification 1. Triangle ABC is similar to triangle BDC 1. Angle ABC = Angle BDC and Angle BCA = Angle BCD 2. BC2 = AC x DC 2. BC ÷ DC = AC ÷ BC because triangle ABC is similar to triangle BDC 3. Triangle ABC is similar to triangle ABD 3. Angle ABC = Angle ADB and Angle BAC = Angle BAD 4. AB2 = AC x AD 4. AB ÷ AD = AB ÷ AC because triangle ABC is similar to triangle ADB 5. AB2 + BC2 = AC x AD + AC x DC = AC (AD + DC) 5. Adding Statement 1 and Statement 2 6. AB2 + BC2 = AC2 6. AD + DC = AC What is the flaw in the student's proof? Justification 2 should be "BC ÷ DC = BC ÷ AC because triangle ABC is similar to triangle BDC." Justification 4 should be "AB ÷ AD = AC ÷ AB because triangle ABC is similar to triangle ADB." Justification 1 should be "Angle ABC = Angle BCD and Angle BCA = Angle DBC." Justification 3 should be "Angle ABC = Angle BAD and Angle BAC = Angle ABD." I got A
Jim makes the chart shown below to prove that triangle APD is congruent to triangle BPC. Statements Justifications In triangles APD and BPC; DP = PC Sides of equilateral triangle DPC are equal In triangles APD and BPC; AD = BC Sides of square ABCD are equal In triangles APD and BPC; angle ADP = angle BCP Angle ADC = angle BCD = 90° and angle ADP = angle BCP = 90° - 60° = 30° Triangles APD and BPC are congruent SSS postulate What is the error in Jim's proof? He writes DP = PC instead of DP = PB. He writes AD = BC instead of AD = PC. He assumes the measure of angle ADP and angle BCP as 30° instead of 45°. He assumes that the triangles are congruent by the SSS postulate instead of SAS postulate. I got D
Look at the figure. A triangle ABC is drawn. D is a point on BC such that BD is equal to DC. A straight line joins points A and D. This line extends down till a point E below the triangle so that AD is equal to DE https://www.google.com/search?q=michelson+interferometer&tbm=isch&tbs=simg:CAQSUxpRCxCo1NgEGgIICgwLELCMpwgaKgooCAESAv8HGiC6GF14925ruJlWfnVFWaB7_1LCSWid4Wbm1RFAFpgashQwLEI6u_1ggaCgoICAESBCLA13YM&sa=X&ei=z3gyU8LkD4rYoATT34LQBA&ved=0CCQQwg4oAA Based on the figure, which pair of triangles is congruent by the Side Angle Side Postulate? Triangle ABD and Triangle ECD Triangle ABC and Triangle ECD Triangle ABD and Triangle ADC Triangle ADC and Triangle ABC I got B
5. The figure below shows a trapezoid, ABCD, having side AB parallel to side DC. The diagonals AC and BD intersect at point O. https://lh4.ggpht.com/EhZck5Kpe2-dBsD3vOGO_JfCFon3rAikMIlvqtDWWMu5H90xiku1xzvQ7K1QDpUZ3u4WuEM=s155 ABCD is a trapezoid with DC parallel to AB. Diagonals AC and DB intersect at point O If the length of AO is double the length of CO, the length of BO is half of the length of AB double the length of DO one-fourth the length of AC equal to the length of AO I got B
6. Adrian is using an indirect method to prove that segment DE is not parallel to segment BC in the triangle ABC shown. A triangle ABC is shown. D is a point on side AB and E is a point on side AC. Points D and E are joined using a straight line. The length of AD is equal to 5, the length of DB is equal to 3, the length of AE is equal to 6 and the length of EC is equal to 4. He starts with the assumption that segment DE is parallel to segment BC. Which inequality will he use to contradict the assumption? 5:3 ≠ 6:10 5:8 ≠ 6:4 5:8 ≠ 6:10 5:3 ≠ 5:6 I got C
The figure below shows segments PQ and RS which intersect at point T. Segment PR is parallel to segment SQ. Two line segments PQ and RS intersect at T. Segments PR and SQ are parallel to each other. Which of these facts is used to prove that triangle PTR is similar to triangle QTS? Line segment RT is congruent to line segment TS because corresponding parts of congruent triangles are congruent. Line segment PR is congruent to line segment SQ because parallel segments are congruent. Angle PTR is congruent to angle QTS because they are vertical angles. Angle PRT is congruent to angle QST because they are vertical angles.
I got c
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