Mathematics
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OpenStudy (anonymous):
@31356! Quadratic Formula! :D
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OpenStudy (31356):
Here I am :D
OpenStudy (anonymous):
hi! :D
OpenStudy (31356):
Hey! :D
OpenStudy (anonymous):
ok... so it was
6x^2+7x-5=0, right?
OpenStudy (31356):
Indeed :D
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OpenStudy (anonymous):
so 6 is a
7 is b
-5 is c
ok?
OpenStudy (31356):
Okay :D
OpenStudy (anonymous):
so the quadratic formula is:
\[x=(-b±√(b^2-4ac))/2a\]
OpenStudy (31356):
Indeed :D
OpenStudy (anonymous):
so I plug in 7 for b first.
\[x=(-7±√(7^2-4ac))/2a\]
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OpenStudy (31356):
On my paper, I plugged in all of the numbers :D
OpenStudy (anonymous):
then I plug in 6 for a
\[x=(-7±√(7)^2(-4)(6)c))/2a\]
OpenStudy (31356):
Okay :D
OpenStudy (anonymous):
then I plug in -5 for c.
oh and I plug them in one at a time to keep them straight in my head... :D
\[x=(-7±√(7)^2(-4)(6)(-5)))/2(6)\]
OpenStudy (31356):
Okay, lol :D
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OpenStudy (anonymous):
so from there I simplify.
OpenStudy (31356):
Yes :D
OpenStudy (anonymous):
Normally, I start with the b^2 - 4ac part...
OpenStudy (31356):
LOL, I know what I did wrong
OpenStudy (anonymous):
ok!
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OpenStudy (31356):
I was thinking square root of 49 but it's 7 lol :D
OpenStudy (31356):
Thanks, I understand the whole process now, lol :D
OpenStudy (anonymous):
:D yay! haha :D
OpenStudy (31356):
Thx for the medal, lol :D
OpenStudy (anonymous):
:D
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OpenStudy (31356):
My lifesaver & Smar tScore gainer :D
OpenStudy (anonymous):
:P you help my smartscore quite a bit too :D
OpenStudy (anonymous):
kk gtg i got mentioned.... like 3 times
OpenStudy (31356):
Cool! :D
OpenStudy (31356):
Okay, lol :D