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Mathematics 21 Online
OpenStudy (anonymous):

@31356! Quadratic Formula! :D

OpenStudy (31356):

Here I am :D

OpenStudy (anonymous):

hi! :D

OpenStudy (31356):

Hey! :D

OpenStudy (anonymous):

ok... so it was 6x^2+7x-5=0, right?

OpenStudy (31356):

Indeed :D

OpenStudy (anonymous):

so 6 is a 7 is b -5 is c ok?

OpenStudy (31356):

Okay :D

OpenStudy (anonymous):

so the quadratic formula is: \[x=(-b±√(b^2-4ac))/2a\]

OpenStudy (31356):

Indeed :D

OpenStudy (anonymous):

so I plug in 7 for b first. \[x=(-7±√(7^2-4ac))/2a\]

OpenStudy (31356):

On my paper, I plugged in all of the numbers :D

OpenStudy (anonymous):

then I plug in 6 for a \[x=(-7±√(7)^2(-4)(6)c))/2a\]

OpenStudy (31356):

Okay :D

OpenStudy (anonymous):

then I plug in -5 for c. oh and I plug them in one at a time to keep them straight in my head... :D \[x=(-7±√(7)^2(-4)(6)(-5)))/2(6)\]

OpenStudy (31356):

Okay, lol :D

OpenStudy (anonymous):

so from there I simplify.

OpenStudy (31356):

Yes :D

OpenStudy (anonymous):

Normally, I start with the b^2 - 4ac part...

OpenStudy (31356):

LOL, I know what I did wrong

OpenStudy (anonymous):

ok!

OpenStudy (31356):

I was thinking square root of 49 but it's 7 lol :D

OpenStudy (31356):

Thanks, I understand the whole process now, lol :D

OpenStudy (anonymous):

:D yay! haha :D

OpenStudy (31356):

Thx for the medal, lol :D

OpenStudy (anonymous):

:D

OpenStudy (31356):

My lifesaver & Smar tScore gainer :D

OpenStudy (anonymous):

:P you help my smartscore quite a bit too :D

OpenStudy (anonymous):

kk gtg i got mentioned.... like 3 times

OpenStudy (31356):

Cool! :D

OpenStudy (31356):

Okay, lol :D

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