Multiply
that is the picture of what the problem looks like because i cant type it here
cancel top and bottom watever u can
what does the Dot mean
\(\large \frac{10y^4}{b^3y} \bullet \frac{3b^2}{4y}\) means \(\large \frac{10y^4}{b^3y} \times \frac{3b^2}{4y}\)
it is same as : \(\large \frac{10y^4\times 3b^2}{b^3y\times 4y} \)
first cancel out numbers : 2 goes in both 10 and 4 right ?
\(\large \frac{10y^4\times 3b^2}{b^3y\times 4y} \) cancel 2 in both top and bottom : \(\large \frac{5y^4\times 3b^2}{2b^3y\times y} \)
fine ?
next cancel y's, wat do u get ?
the same one without the Y's ?
\(\large \frac{10y^4\times 3b^2}{b^3y\times 4y} \) cancel 2 in both top and bottom : \(\large \frac{5y^4\times 3b^2}{2b^3y\times y} \) \(\large \frac{15y^4\times b^2}{2b^3y\times y} \) canceling y's : \(\large \frac{15y^2\times b^2}{2b^3} \)
finaly cancel out top two b's in bottom 3 b's that leaves 1 b in the bottom
\(\large \frac{10y^4\times 3b^2}{b^3y\times 4y} \) cancel 2 in both top and bottom : \(\large \frac{5y^4\times 3b^2}{2b^3y\times y} \) \(\large \frac{15y^4\times b^2}{2b^3y\times y} \) canceling y's : \(\large \frac{15y^2\times b^2}{2b^3} \) cancel b's : \(\large \frac{15y^2}{2b} \)
let me knw if smthng doesnt make sense
so 15y^2 /2b is the final answer?
yup!
thanks
yw
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