Question

Find all solutions of the given equation. csc^2 θ − 2 = 0

Answer 1

It's an equation with a single trig function, so there's no harm in taking the 2 over. Now, do you know what csc is?

Answer 2

1/cos^2 x - 2 = 0 --> 1/cos^ x = 2 -> cos ^2 x = 1/2
cos x = V2/2 and cos x = -V2/2
a) cos x = V2/2 = cos Pi/4 --> x1 = ......
b) cos x = -V2/2 = cos 3Pi/4 -> x2 = ......

Answer 3

if your question is resolving (cos(x))^2 -2=0 then it doesn't have a solution because the cosinus is always between -1 and 1 so the square couldn't equal 0