Question

f(x)=x^2 -1 / x^3
what are the critical points of function ?

Answer 1

why dont you find the first derivative of the function?

Answer 2

2x.x^3 - x^2-1.3x^2 / (x^3)^2

Answer 3

uh oh !

Answer 4

this derivative of f(x)=x^2 -1 / x^3

Answer 5

pls simplify , i cant understand it!!!

Answer 6

you need parenthesis around (x^2 - 1)

Answer 7

exacty sir ranga!

Answer 8

okay so now make this first derivative equals to 0, and find out the possible values of x.

Answer 9

I want critical points

Answer 10

first hwo to simplify this function ?

Answer 11

how*

Answer 12

numerator is: 2x.x^3 - (x^2 - 1)3x^2 (It is 3x^2 and NOT 3x^3)
2x^4 - 3x^4 + 3x^2
-x^4 + 3x^2
x^2(-x^2 + 3)

To find critical point, equate dy/dx to zero and solve for x.
Equate numerator to zero and solve for x.

Answer 13

I don't understand .. can you draw ?

Answer 14

oo i misd that mistake sorry!!

Answer 15

yup ur derivative is wrong!