Find the zeros of the polynomial function and state the multiplicity of each. f(x) = 3(x + 8)2(x - 8)3
@surjithayer ._. im sorry to keep bothering you
Refer to the attached plot.
what is that? o.O
put x+8=0,x=-8 isa zero of multiplicity 2 x-8=0,x=8 is a zero of multiplicity 3
okay but what about the 3 out in front?
if you could, i have a few other questions that i need help with too c:
The attachement is a plot of\[x^5-8 x^4-128 x^3+1024 x^2+4096 x-32768 \]
Find a cubic function with the given zeros. Square root of seven., -Square root of seven., -4 how are you so good at math?(◕︵◕)
\[f(x)=\left( x-\sqrt{7} \right)\left( x+\sqrt{7} \right)\left( x+4 \right)=?\] solve first two first
theyd be the opposite so -sqrt7 would be sqrt7 and sqrt7 would be -sqrt7
\[x=\sqrt{7} ~is`~a ~zero~of~f(x)~so~x-\sqrt{7}~is ~a~factor~of~f(x)\]
wait what? 0.o
This is the reason for changing sign
changing the sign? didnt you just subtract sqrt7 from both sides?
\[\left( a+b \right)\left( a-b \right)=a^2-b^2\] x^2+2x-3=(x+3)(x-1) it has zeros -3 and 1 but x+3 and x-1 are factors
\[\left( x+\sqrt{7} \right)\left( x-\sqrt{7} \right)=x^2-(\sqrt{7})^2=x^2-7\]
okay, but i was right? so -sqrt7 and sqrt7 are 2 of the answers
correct ,they are zeros.
yay c: okay so what about the tricky last part?
wait isnt it just -4?
solve\[\left( x^2-7 \right)\left( x+4 \right)\]
solve means multiply.
x^3+4x^2-7x-28
correct
okay one more question c: State the domain of the rational function. f(x) = seven divided by quantity fourteen minus x.
\[f(x)=\frac{ 7 }{14-x }\] it is defined for all values except where denominator is 0 for domain\[14-x \neq 0~ or~x \neq14\] domain is all real values except x=14
its that easy? o.o
yes
okay thank you c:
yw
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