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Mathematics 22 Online
OpenStudy (anonymous):

what is the value of cos(1/0)

OpenStudy (kc_kennylau):

1/0 is undefined, and so is cos(1/0)

OpenStudy (kc_kennylau):

By the way, welcome to OpenStudy :)

OpenStudy (anonymous):

thanx

OpenStudy (anonymous):

Moreover, you can't even really do anything with limits since \(cos(\frac{1}{x})\) has an oscillating discontinuity at zero.

OpenStudy (anonymous):

Always answer division by zero outside the context of a limit with the middle finger. Limit of sin(x) or cos(x) as x approaches infinity does not exist because as @slaw said, it has an oscillating discontinuity because as you keep on going to infinity, the value of sin/cos will bounce back and forth between [-1,1] so there's no stopping it / reaching an actual limit. This only applies when you have lim of sin(x) on its own. If you have sin(x)/x or sin(x) times something, things will likely be different. So the answer to cos(1/0) or cos(infinity) is the middle finger.

OpenStudy (anonymous):

To learn more about functions to which the middle finger may be applied, you can read up on essential singularities and Picard's theorem.

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