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Mathematics 23 Online
OpenStudy (anonymous):

Determine if the graph is symmetric about the x-axis, the y-axis, or the origin. 1. r = 4 - 4 cos θ 2. r = 4 cos 5θ

OpenStudy (anonymous):

need help?

OpenStudy (mathmale):

In #1: copy down r = 4 - 4 cos θ. Next, replace that θ by (-θ), and simplify. Is the 2nd equation the same as before, or different from what it was before? What does this result tell you about the symmetry of the graph?

OpenStudy (anonymous):

Also more help 1. In the equation r = 4, θ is free. The graph of this equation is, therefore, ... 2. ) for various values of r shows us that we are tracing out the y-axis. ... We graph one cycle of r = 6 cos(θ) on the θr-plane3 and use ... x-axis and gradually pulls in towards the origin as it moves towards the ...... indeed symmetric about the x-axis.

OpenStudy (anonymous):

1. x-axis only

OpenStudy (anonymous):

2. origin only?

OpenStudy (anonymous):

@mathmale @TICOxTICO

OpenStudy (anonymous):

yes you are very welcome of our thesis's are they correct?

OpenStudy (anonymous):

I believe so. If I got the right answer.

OpenStudy (anonymous):

double check on the wiki or other recourse of info. ^-^

OpenStudy (anonymous):

by the way I want to give you something.

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

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OpenStudy (anonymous):

that

OpenStudy (anonymous):

lol nice.

OpenStudy (anonymous):

your welcome

OpenStudy (anonymous):

the epic face

OpenStudy (anonymous):

@mathmale Does this look correct?

OpenStudy (mathmale):

Take a look at this graph produced by wolframalpha.com for Part #2: http://www.wolframalpha.com/input/?i=r+%3D+4+cos+5%CE%B8 Do you see any symmetry here? If so, what kind? You might want to experiment with wolframalpha.com, graphing r=4 cos theta, 4 cos 2 theta, 4 cos 4theta, 4 cos 5 theta, and so on. Use the results to check your answer for Part #2.

OpenStudy (anonymous):

It's the first graph I'm looking at right?

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