Question

Please help

What are all the real and complex roots of the polynomial x3 − 6x2 + 9x − 4, given that one root is x = 1?

Answer 1

if x=1 is one of the roots you can divide the polunomial by (x-1), you will get a polynomial, then you can use the quadratic formula to find the other roots, including complex roots

Answer 2

@lucaz like this ? (x−1) x3−6x2+9x−4
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Answer 3

(x3−6x2+9x−4) / (x-1)

Answer 4

from this long division you get x^2-5x+4, find the roots of this quadratic..
(x-1)(x-4)
x=1
x=4
the factored form of the original polynomial is:
(x-1)(x-1)(x-4)

Answer 5

so @lucaz (x-1)(x-1)(x-4) is the answer?

Answer 6

this is the factorization of the polynomial, from this you can get the roots, x=1 and x=4

Answer 7

o ok so x=1 and x=4, @lucaz

Answer 8

yes, when x is 1 and when x is 4 the polynomial is equal to zero, so these are the roots

Answer 9

thank you very much

Answer 10

no problem

Answer 11

can u help me with one more @lucaz