An expression is shown below: f(x) = -16x2 + 24x + 16 Part A: What are the x-intercepts of the graph of f(x)? Show your work. Part B: Is the vertex of the graph of f(x) going to be a maximum or minimum? What are the coordinates of the vertex? Justify your answers and show your work. Part C: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part A and Part B to draw the graph.
b- maximum
why ?
x intercept =-b/2a =-24/(2*-16)=24/32=12/16=6/8=3/4=0.75
b- maximum because " a " =-16 which is < (less) than zero !
whoaaa lol u sure
x=0.75 ;find y by inputting x in f(x)
it never mentioned an "a" tho
-16(0.75)^2+24*(0.75)+16
f(x)=-16x^2+24x+16 f(x)=ax^2+bx+c
where did the a come from
a=-16 b=24 c=16
f(x)=ax^2+bx+c - quadratic equation
on comparing we get "a" ! is it clear ?
if u say so
and part c ?
coordinates of vertex are (x,y)
f(x)=25
vertex is (0.75,25)
u know how to plot the graph right ?
no
find f(x ) by assuming x=0.5,x=1 corresponging values of f(x) can be found similarly
and on x and y axis of coordinate system plot those (x,y) points and draw a smooth curve which is your graph !
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