Part A: Write the expression x2 - 18x + 45 as a product of two linear expressions. Show your work and justify each step. Part B: Rewrite x2 - 6x + 9 as a square of a linear expression. Part C: Do the expressions in parts A and B have a common factor? Justify your answer.
oh where is said x2, I meant x^2
When it says that, it just means to factor them like in this one \[x^2+2x+1=(x+1)(x+1)\] can you do it now?
Um, I'm not really sure what that means.
ok, have you heard of completing the square yet?
I might have.
Like, if you explain it, I think I know what it is.
This should help explain better than I can https://www.khanacademy.org/math/algebra/quadratics/factoring_quadratics/v/Example%201:%20Solving%20a%20quadratic%20equation%20by%20factoring
I double checked, yours are just factoring
ok thank you!
Check back after you watch it, and we can go over the rest of the problem
ok
Okay, I finished
@FibonacciChick666
alright, so do you have any ideas on how to start part A?
@QuestionsWolf
we find a number that adds to -18 and multiplies to 45
good! so now, it's easiest to start with the factors of 45 can you tell me them?
45 and 1, 5 and 9, 15 and 3,
now, do any of those add to 18?
15 and 3
good, now the only issue is that we need a -18, any ideas on how we can get that?
Have a number that is negative
tell me the two numbers then? I don't quite understand your response
Um, -15 and -3
perfect! so then what does \(x^2-18x+45=?\)
x^2 - 15 - 3 + 45
uhm so go back and look at the factoring video or my original response. You want two things multiplying each other
to = that polynomial
Im not really sure what you are asking?
remember this: When it says that, it just means to factor them like in this one x2+2x+1=(x+1)(x+1) can you do it now? So you want that format
okay, let me see.
x^2 - 15x - 3x + 45 (x^2 - 15x) + (-3x + 45) x(x - 15) + -3(x + -15) (x - 15)(x - 15) (x - 15)(x - 3)
yup yup can't say I've ever seen it broken down that way, but that works
Oh xD well thank you!
so you just follow the same algorithm for part b
really great idea for expanding it like that... I never would have thought of it
Thank you, and thank you for your help! :)
np if you have problems with the next part just message me
Join our real-time social learning platform and learn together with your friends!