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MIT 8.01 Physics I Classical Mechanics, Fall 1999 18 Online
OpenStudy (anonymous):

two blocks of mass5kg and 7 kg are connected by a rope of m 4 kg an upward force f = 200 N is applied on the system .acceleration in the system is

OpenStudy (anonymous):

16.67 m/s^2. Add the masses and divide by the force.

OpenStudy (anonymous):

f/M where M is total block + rope = 16 kg then a=12.5m/s^2

OpenStudy (vincent-lyon.fr):

The acceleration is much smaller since the weights of the different parts will counteract force f.

OpenStudy (anonymous):

it is 200/16 = 12.5m/sec2 ,as the two block and rope can be treated as one point mass object so from F=ma we have the answer.

OpenStudy (vincent-lyon.fr):

No, it isn't. Read my post just above.

OpenStudy (anonymous):

treat the rope mass systems separately.... draw free body diagram .... mass of rope should be considered..... that mass would create weight of mg.... and solve the question!!!!

OpenStudy (anonymous):

or else see tata mcgraw hills for iitjee( newtons laws of motion )....

OpenStudy (anonymous):

In subject it is not stated if the system is subject gravity, it is making sense to consider system initially without any gravity effect.

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