Question

Which of these orbital designations are invalid?
a)4s
b)2d
c)3f
d)3p

Answer 1

When n= 2, there are s and p-orbitals
When n = 3, there are s, p and d-orbitals
4f is possible

Answer 2

i dont understand how you can tell

Answer 3

read this carefully When n = 3, there are s, p and d-orbitals

Answer 4

i still dont understand how to use the model to understand this

Answer 5

In Bohr´s model, electrons are in
energy levels are labeled as K,L,MN,..
MAin quantum number n = 1,2,3,4,..

In quantum mechanical model there are suborbitals s,p,d,f

Shape of suborbital is described by side quantum number l.
It can have values 0,1,..n-1

for s , l = 0 ,
for p l = 1 ,
or d l = 2
and for f l = 3

So, if n = 1 (K) l = 0 (remeber highest value can be n-1)
in L, n = 2 and l can be 0 (s) or 1 (p)

in M n = 3, and l = 0, 1, 2. 2 is for d suborbital

Then N (n = 4) l = 0,1,2,3. For f l = 3

When inner electron levels are filled (each suborbital may have two
electrons with opposite spins), there are more suborbitals in outer
electron levels.