Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (helpblahblahblah):

MEDAL: What is the length of side A B? (attached) A. 10 feet B. 11 feet C. 12 feet D. 13 feet

OpenStudy (helpblahblahblah):

OpenStudy (helpblahblahblah):

i think 12 feet

OpenStudy (cggurumanjunath):

10

OpenStudy (helpblahblahblah):

can u plz explain?

OpenStudy (anonymous):

yeah its 10

OpenStudy (anonymous):

I'll explain how

OpenStudy (helpblahblahblah):

kk

OpenStudy (cggurumanjunath):

2/3

OpenStudy (cggurumanjunath):

ratios !

OpenStudy (cggurumanjunath):

6/9 =8/12 =2/3

OpenStudy (cggurumanjunath):

x/15=2/3

OpenStudy (cggurumanjunath):

is it clear ? solve for x using above equation ! @HelpBlahBlahBlah

OpenStudy (helpblahblahblah):

no i dont really get that

OpenStudy (anonymous):

similarity \[JK/AC = LK/CB =JK/AB\]

OpenStudy (anonymous):

is this clear so far ?

OpenStudy (helpblahblahblah):

yeah

OpenStudy (anonymous):

look at the triangles please

OpenStudy (helpblahblahblah):

okay

OpenStudy (anonymous):

ok then substitute , you have the number in the drawing so you will have \[\frac{ 9 }{ 6 } = \frac{ 12 }{ 8 }= \frac{ 15 }{ AB }\]

OpenStudy (anonymous):

is this clear till now ?

OpenStudy (helpblahblahblah):

yes

OpenStudy (anonymous):

now you can use one of those two fraction to get the AB so you can do this \[\frac{ 9 }{ 6 } = \frac{ 15 }{ AB }\] use the cross multiplication method . AB= \[\frac{ 6 \times 15 }{ 9}\] = 10 OR AB=\[\frac{ 8\times 15 }{ 12 }\] = 10

OpenStudy (anonymous):

please let me know if you understand this now @HelpBlahBlahBlah :)

OpenStudy (helpblahblahblah):

ohhhh okay that makes since thanks soooo mcuh :)

OpenStudy (anonymous):

you're more than welcome , good luck :)

OpenStudy (helpblahblahblah):

lol :)

OpenStudy (anonymous):

hehe :)

OpenStudy (helpblahblahblah):

haha thanks for fanning back :)

OpenStudy (anonymous):

you're welcome :) I hope I can help again

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!