Question

Solve the following equation:

8y^3 − 2y^2 − 6y = 0

Answer 1

@hello1213

Answer 2

what is common between all of the terms?

Answer 3

2y?

Answer 4

yes! so now we have\[2y(4y^2-2y-6)\]

Answer 5

yup, =0, now what?

Answer 6

\[=2y \left(4 y^2-y-3 \right)\]

Answer 7

yeah the middle term should be y not 2y.

Answer 8

I got it, now I factor it out more?

Answer 9

4*-3=-12
4-3=1
4*-3=-12

Answer 10

yes.

Answer 11

4-3=1 is the right one

Answer 12

2y(y+4)(y-3)?

Answer 13

2y+4?

Answer 14

2 y (y-1) (4 y+3)=0
y= 0, 1 and -3/4

Answer 15

thank you ! :)