One more problem to check please ^_^ , again will take me a second to type all

Question

anonymous · Answer

$$9^{x^2-2x}=27^{x^2+1}$$
My final answer was x=-3
x=-1,
both were invalid when I plugged them back into the equation. Is that possible?

johnweldon1993 · Answer

Well lets do it this way...how did you arrive at your results?

johnweldon1993 · Answer

And by that I mean your result of "Plugging them back in giving an invalid result"

johnweldon1993 · Answer

Because when I plug them in I certainly get the correct result

anonymous · Answer

$$(3^2)^{x^2-2x}=(3^3)^{x^2+1}$$
$$\log_{3}3^{2x^2-4x}=\log_{3}3^{3x^2+3}  $$
$$2x^2-4x=3x^2+3$$
$$x^2+4x+3=0$$

anonymous · Answer

X=-3,-1

johnweldon1993 · Answer

Right...-3 and -1 are indeed the correct roots...but now show the steps of plugging them back in to check

anonymous · Answer

and then i plugged back in the values of x back into the original equation, but they didn't seem to add up when i did so

phi · Answer

-1 definitely works.

anonymous · Answer

i see what i was doing wrong

anonymous · Answer

i messed up my negatives on my calculator; wasn't isolating them properly.

johnweldon1993 · Answer

Ahh...that'll do it :)

anonymous · Answer

thank you