Give a formula for the nth term of the arithmetic sequence...
\[-1,0,1,2, . . .\]
@ikram002p @lexii1998
im getting your help back
@SolomonZelman @amistre64
thanks.
3 i think
\[a_{n-1}+1=a_{n}\] like this ?
it in squincal order soit -1,0,1,2,3
I think the formula is \[t_{n}= t_{1} +(n-1)_{d}\]
the directions read, "Give a formula for the nth term of the arithmetic sequence..."
an = ao + d(n-1) is the usual arithmetic formula ....
yeah, your t verion is fine ... but d is not a subsctipt
I know d represents the common difference in the sequence so that would be -1?
d is the number we use to get from 0 to 1 .... 0 + d = 1
So it's not the common difference?
-1,0,1,2,3,4,5,6 it is the common different ... between any 2 terms. -1 + d = 0 0 + d = 1 1 + d = 2 2 + d = 3 etc ...
if we use d=-1 ... we dont generate their sequence -1 -1 = -2 0 - 1 = -1 it just doesnt work out
okay I see! thanks for the help... so the answer here would be \[t_{n}=n-2\]
that seems fair yes
its the set of numbers (1,2,3,4,5,...) - 2 :)
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