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Mathematics 20 Online
OpenStudy (anonymous):

Give a formula for the nth term of the arithmetic sequence...

OpenStudy (anonymous):

\[-1,0,1,2, . . .\]

OpenStudy (jlg030597):

@ikram002p @lexii1998

OpenStudy (jlg030597):

im getting your help back

OpenStudy (anonymous):

@SolomonZelman @amistre64

OpenStudy (anonymous):

thanks.

OpenStudy (anonymous):

3 i think

OpenStudy (anonymous):

\[a_{n-1}+1=a_{n}\] like this ?

OpenStudy (anonymous):

it in squincal order soit -1,0,1,2,3

OpenStudy (anonymous):

I think the formula is \[t_{n}= t_{1} +(n-1)_{d}\]

OpenStudy (anonymous):

the directions read, "Give a formula for the nth term of the arithmetic sequence..."

OpenStudy (amistre64):

an = ao + d(n-1) is the usual arithmetic formula ....

OpenStudy (amistre64):

yeah, your t verion is fine ... but d is not a subsctipt

OpenStudy (anonymous):

I know d represents the common difference in the sequence so that would be -1?

OpenStudy (amistre64):

d is the number we use to get from 0 to 1 .... 0 + d = 1

OpenStudy (anonymous):

So it's not the common difference?

OpenStudy (amistre64):

-1,0,1,2,3,4,5,6 it is the common different ... between any 2 terms. -1 + d = 0 0 + d = 1 1 + d = 2 2 + d = 3 etc ...

OpenStudy (amistre64):

if we use d=-1 ... we dont generate their sequence -1 -1 = -2 0 - 1 = -1 it just doesnt work out

OpenStudy (anonymous):

okay I see! thanks for the help... so the answer here would be \[t_{n}=n-2\]

OpenStudy (amistre64):

that seems fair yes

OpenStudy (amistre64):

its the set of numbers (1,2,3,4,5,...) - 2 :)

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