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Chemistry 19 Online
OpenStudy (aravindg):

Organic help @abbot

OpenStudy (aravindg):

1. Major product in photobromination of 2 methyl butane is _____

OpenStudy (abb0t):

This is similar to what we went over last time, this is a radical reaction. Formation of more stable product. |dw:1396882725530:dw|

OpenStudy (aravindg):

So 3 degree carbon gets bromine here.

OpenStudy (aravindg):

2 BROMO 2 METHYLBUTANE right?

OpenStudy (abb0t):

|dw:1396882848440:dw|

OpenStudy (abb0t):

oh wait, you do. Lol Soryr.

OpenStudy (aravindg):

Yeah lol so 2 BROMO 2 METHYLBUTANE right?

OpenStudy (aravindg):

How about the product of treating ethyl benzene and n bromo succinimide?

OpenStudy (aravindg):

@abb0t

OpenStudy (abb0t):

brominate the alkane, not the benzene.

OpenStudy (aravindg):

So n bromo succinimde is a brominating reagent?

OpenStudy (abb0t):

yes. another radical reaction. is it just NBS or is there another agent in solution? like CCl\(_4\) or something?

OpenStudy (aravindg):

Just NBS How about this qn: Identify the order of basicity:

OpenStudy (abb0t):

Well, look at their conjugate structures and then draw out their resonance strcutrues.

OpenStudy (aravindg):

Does the N atom of 2nd compound get involved in resonance?

OpenStudy (abb0t):

Yes. It can partake in resonance.

OpenStudy (aravindg):

I have a doubt in that.

OpenStudy (aravindg):

And what factor should we use to differentiate 1 and 3?

OpenStudy (abb0t):

Remember, resonance is simply delocalization of electron density. This gives the molecle a stabilizing effect, since it can be distributed in a greater area.

OpenStudy (abb0t):

One has an oxygen, while the other has a carbon.

OpenStudy (aravindg):

ofc I see that lol..I asked the factor :P

OpenStudy (abb0t):

|dw:1396883628362:dw|

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