Question

Graphing a Parabola (NEED HELP)
Follow the directions below. Use your results to answer the questions.

Make a t-table of values for y = x2 + 4x + 1. A suggestion is to begin your values with -5.
Graph the points on graph paper and draw the parabola.
Fold the paper vertically, so that the two sides of the parabola are touching each other.
Unfold the paper.

List your ordered pairs from the table. Use parenthesis for each pair, such as (-1,2)

Answer 1

Alright so it says to make a t-table (if you want to or need to...go ahead :) but I'm just going to graph this...

So it is a normal parabola...with vertex

\[\large -\frac{b}{2a} = - \frac{4}{2} = -2 \] so a vertex at (-2 , -3) (got the -3 by plugging in -2 to the equation

So this will look like

Answer 2

Wow terrible drawing XD but that IS the general idea :)

Answer 3

@johnweldon1993 how would i put this into a t-table ?

Answer 4

Alright so the t-table would look like



so it is basically saying...when you plug -5 into your equation...what will the equation equal? and when you find that...you plug it into t-table under the 'y' section...but next to the -5 from the 'x' section

Answer 5

So I'll do that -5 for you :)

when you plug in -5 to your equation...you get

\[\large x^2 + 4x + 1\]
becomes
\[\large (-5)^2 + 4(-5) + 1\]
\[\large 25 - 20 + 1\]
\[\large 5 + 1 = 6\]

Answer 6

so then in the table we will have