Log base 7 (3x-11) find domain and write in interval notation
\[\log_{7}(3x-11) \]
can you tell me what the domain is for y=log(x)?
0? or infinity?
it is a range of numbers not just one number
Then I am lost, sorry
how about a graph of log(x)=y|dw:1396987410805:dw| recall the domain is the set of x values where the relation (function in this case) exists
looking at my graph for y=log(x) can you tell me for what x values the function exists?
at 3 or 4? cant tell without numbers
myininaya is showing that the graph of ln(x) exists only for x>0 ln(0) will give you a math error on your calculator. that is because e^x =0 is not true for any x
ok that vertical line represents x=0 look at that graph it continues for much greater x values
ok
So it will be infinite positive numbers until we reach x?
the set is positive numbers or you could say (0,infinity)
both of these say things that we can only have positive numbers for our domain anyways we are looking at y=log(f(x)) we need f(x) to be positive which means we need f(x)>0
so 3x-11>0?
omg you took the words right out of my mouth good job
solve that for x and you are done
well i guess you are also require to put it in interval notation after that
Lol sometimes words just confuse me. I am better with numbers i feel. so if i can find the proper way to set it i can complete it you know?
And yes. Can you explain to me how do go about doing so? My first guess would be (11/3,infinity)
that is right
To review, the domain of a function are the numbers it "accepts" (without causing an error or being undefined). Lots of functions have a domain of all real numbers. Some, like the log, only accept numbers bigger than zero.
Lol thank u guys, i feel so slow until i actually get going. can I try one more with u to make sure i got it?
do you want me to make up one or do you have one?
I am taking practice problems from the book so i have one.
\[\log (x-5)+\log(8-.5x)\]
This might seem very elementary but when there is no base it is recognized as 10 right?
yes
this is another domain question?
yea
you can go about this two different ways you can find the domain of log(x-5) and the domain of log(8-.5x) and then find the intersection of those sets to find the domain of log(x-5)+log(8-.5x) or you can find condense into one log and then remember that if you have y=log(f(x)) the domain is f(x)>0
do you know what i mean by intersection?
Im pretty sure i do. I think id like the first way a little better.
so what is the domain of log(x-5)?
5
the domain of a function are the numbers it "accepts"
\[-\infty,5\]
so can i ask what inequality you solved to get that?
uh oh lol , means im wrong
x-5=0
is that an inequality?
Dangit x-5>0?
ok great and you added 5 on both sides right do you know how to read x>5?
like what does that mean?
All numbers greater than 5 are allowed?
so you mean to say the domain of log(x-5) is (5,inf)?
inf=infinity
Yes, i think lol
it is (5,inf) means 5 and any number after 5 without actually including 5
so any number after 5 lol
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