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Mathematics 21 Online
OpenStudy (anonymous):

How to simplify the following expression : A'C(A'BD) + A'BC'D' + AB'C ? i am stuck no matter how i try .

OpenStudy (anonymous):

Boolean Algebra, no?

OpenStudy (anonymous):

Is that A complement? i.e., not a

ganeshie8 (ganeshie8):

use kmap

OpenStudy (anonymous):

the answers must using boolean algebra to simply it

OpenStudy (anonymous):

mathbabrz..yup..its A'

ganeshie8 (ganeshie8):

AA = A

ganeshie8 (ganeshie8):

A'C(A'BD) + A'BC'D' + AB'C becomes A'CBD + A'BC'D' + AB'C

OpenStudy (anonymous):

yup...then ..i try A'B( CD+C'D')+AB'C' AND....i get stuck until here..huhu

OpenStudy (anonymous):

A'B( CD+C'D')+AB'C

OpenStudy (anonymous):

I wish I remembered kmaps

OpenStudy (anonymous):

too busy to look it up right now. good luck :)

OpenStudy (anonymous):

it ok mathbrz..thank u =)

ganeshie8 (ganeshie8):

A'C(A'BD) + A'BC'D' + AB'C becomes A'CBD + A'BC'D' + AB'C thats it, we cannot simplify further

ganeshie8 (ganeshie8):

your expression is equivalent to sum of min terms : 7, 4, 10, 11

OpenStudy (anonymous):

really?hahaha... i thought it can be simplify futher..

ganeshie8 (ganeshie8):

you can only combine 10 and 11,

ganeshie8 (ganeshie8):

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