Mathematics
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OpenStudy (anonymous):
How to simplify the following expression : A'C(A'BD) + A'BC'D' + AB'C ? i am stuck no matter how i try .
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OpenStudy (anonymous):
Boolean Algebra, no?
OpenStudy (anonymous):
Is that A complement? i.e., not a
ganeshie8 (ganeshie8):
use kmap
OpenStudy (anonymous):
the answers must using boolean algebra to simply it
OpenStudy (anonymous):
mathbabrz..yup..its A'
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ganeshie8 (ganeshie8):
AA = A
ganeshie8 (ganeshie8):
A'C(A'BD) + A'BC'D' + AB'C
becomes
A'CBD + A'BC'D' + AB'C
OpenStudy (anonymous):
yup...then ..i try A'B( CD+C'D')+AB'C'
AND....i get stuck until here..huhu
OpenStudy (anonymous):
A'B( CD+C'D')+AB'C
OpenStudy (anonymous):
I wish I remembered kmaps
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OpenStudy (anonymous):
too busy to look it up right now. good luck :)
OpenStudy (anonymous):
it ok mathbrz..thank u =)
ganeshie8 (ganeshie8):
A'C(A'BD) + A'BC'D' + AB'C
becomes
A'CBD + A'BC'D' + AB'C
thats it, we cannot simplify further
ganeshie8 (ganeshie8):
your expression is equivalent to sum of min terms : 7, 4, 10, 11
OpenStudy (anonymous):
really?hahaha... i thought it can be simplify futher..
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ganeshie8 (ganeshie8):
you can only combine 10 and 11,
ganeshie8 (ganeshie8):
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