Question

I need help finding the ratio of moles of O2 to moles of KClO3. I have calculated there to be .0100 moles of O2, and .0082048 moles of KClO3.

Answer 1

\[\begin{align*}\text{mol of O}_2 : \text{mol of KClO}_3 &= 0.010\;0 : 0.008\;204\;8\\ \\&= \frac{0.010\;0}{0.010\;0\;} : \frac{0.008\;204\;8}{0.010\;0}\\ \\ &\approx 1 : 0.82 \\ \\ &\approx 1 : \dfrac{4}{5} \\ \\ &\approx 5:4\end{align*}\]