In a city, 49% of the adults are male. 24% of the adults are male and rent action-movie DVDs, and 10% of the adults are female and rent action-movie DVDs. If an adult is randomly selected for a survey, what is the probability that the adult rents action-movie DVDs, given that the adult is female? Will Fan+medal!!
@Warriorz13
IDK Man very good at math @IsaiahCC100
Thank you.
Np
Well i think i might have it, @hoblos will you check my work? So 51% of the adults are female, i divided that by .10(adults who are female and rent action movies). I came up with .19607.
suppose A: the adult rents action-movie DVDs B: the adult is female \[P(A|B) = \frac{ P(A∩B) }{ P(B) }\]
you did 0.51/0.1 or 0.1/0.51 ?
I think 0.1/.51
yeah 0.1/0.51 is correct
Thank you @hoblos
any time :)
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