A long time ago, in a galaxy far, far away, Lama Su takes Obi-Wan Kenobi on a tour of the clone factory in Tipoca City on Kamino. In order to obtain the biomass necessary to construct the clones, a gigantic vat is filled with 700 gallons of a solution of liquefied Hutt fat containing 80 pounds of granulated Wookie hair. Then, pure liquefied Hutt fat is pumped into the vat at a rate of 6 gallons per minute, while the well-stirred mixture is removed from the vat at a rate of 9 gallons per minute. After 3 hours of pumping pure Hutt fat into the vat, how many pounds of granulated Wookie hair are left in the vat?
who ever came up with this question should be killed,they screwed up star wars worse than Disney did making that musical
plugin the initial value, solve the constant c
Ok here's how I did it: t=180mins Let H(t)=amount of liquefied Huttfat (in gallons) after t minutes Let W(t)=amount of wookie hair (in pounds) after t minutes \[\frac{ dw }{ dt }\]=rate in(of hair) - rate out(of hair) =[(rate in(of soln)*concentration of soln. coming in)-(rate out (of soln)*concentration of soln coming out)] =(6gal/min*0bl/gal)-(9gal/min*(hair at time t/soln of time t) =0lb/min-9gal*(W lb/ H gal) dW/dt=-9W/(700-3t)=(-9/(700-3t))*dt=dW/W \[\int\limits \frac{ dW }{W }=\int\limits \frac{ -9 }{ 700-3t }dt \rightarrow \ln \left| W \right|=-9\ln \left| 700-3t \right|+c\] \[e^{\ln \left| W \right|}=e^{-9\ln \left| 700-3t \right|} +e^{C}\] are these the right steps to find C and find the amount of wookie hair? If not what steps do I need to add or revise?
this is the worst star wars question ever
scary lol
it looks okay, except for a minor mistake when evaluating integral
you should get : \(\large \int\limits \frac{ dW }{W }=\int\limits \frac{ -9 }{ 700-3t }dt \rightarrow \ln \left| W \right|=\dfrac{-9\ln \left| 700-3t \right|}{-3}+c\)
right ?
Oh yah and the 9 cancelles out 3 yah I see
yes and it simplifies to the wolfram solution click my first reply
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