Question

is anyone good at solving logarithmic equations?

Answer 1

john napier

Answer 2

what equation do you have to solve?

Answer 3

thanks. doing some practice problems.
solve for x:
e^2x-3e^x+2=0

I thought of e^x(e-3)+2 but don't know where to go from here (if it is correct)

Answer 4

oh no
factor

Answer 5

\[e^2x-3e^x+2=0\]
\[(e^x-2)(e^x-1)=0\] so
\[e^x-2=0\iff e^x=2\iff x=\ln(2)\]for the first factor
second is similar

Answer 6

then ln(2) is .6931.
thanks. I appreciate it.

Answer 7

yw