Question

[calculus] differentiate:
f(x) = (lnx) / x^3

Answer 1

quotient rule for this one
\[(\frac{f}{g})'=\frac{gf'-fg'}{g^2}\] with
\[f(x)=\ln(x), f'(x)=\frac{1}{x}, g(x)=x^3,g'(x)=3x^2\] plug and chug

Answer 2

\[f(x)=x^{-3}lnx\] Or use exponent rules to make this a nice product rule question, I always forget which is negative in the quotient rule.

Answer 3

Thanks guys!