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Mathematics 24 Online
OpenStudy (anonymous):

sec (tan^-1(-4) + sin^-1(1/3)) I know tangent is in the IV quadrant. How can I tell what sin and cos are?

OpenStudy (ankit042):

why is tangent in IV quadrant?

OpenStudy (ankit042):

sin is +ve in 1st and second quadrant

OpenStudy (anonymous):

because it can only occur in the first our fourth qudrant

OpenStudy (anonymous):

the doman is -pi/2<x<pi/2

OpenStudy (anonymous):

thats the domain for the inverse function of tangent

OpenStudy (ankit042):

Hmm that is true! same way you can do for inverse of sin it's range is also in between -pi/2 to pi/2

OpenStudy (anonymous):

so is tangent 8/2 or is it 16/4 i mean i guess it doesnt matter because the proportions would all be the same

OpenStudy (ankit042):

Just use the calculator to get the angles and proceed not sure what is the doubt

OpenStudy (anonymous):

can you simplify sqrt68

OpenStudy (anonymous):

2sqrt 17

OpenStudy (anonymous):

got it

OpenStudy (anonymous):

I believer using cos(A+B) = cos(A)cos(B) - sin(A)sin(B) will do the trick

OpenStudy (anonymous):

why is that

OpenStudy (anonymous):

and then put 1/cos for the sec value?

OpenStudy (anonymous):

yes

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