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Mathematics 14 Online
OpenStudy (anonymous):

what is the value of the summation ∑i=14(2i+6i2)?

OpenStudy (anonymous):

the answer choices A. 180 B. 200 C. 220 D. 240

myininaya (myininaya):

I'm really having trouble understanding your problem? Can you be more clear what your expression is?

OpenStudy (anonymous):

the 4 is at the top of the huge E, under neath it it says i=1, next to it in parenthesis it says (2i + 61^2)

myininaya (myininaya):

so you mean to say this: \[\sum_{i=1}^{4}(2i+6i^2)\]

OpenStudy (anonymous):

yesss

myininaya (myininaya):

you can use some formulas are you can just plug in and then add the terms either way for this one since there isn't many terms

myininaya (myininaya):

evaluate the expression 2i+6i^2 for i=1 for i=2 for i=3 for i=4 then you will have four terms add them

myininaya (myininaya):

have you plugged in 1 for i in the expression 2i+6i^2?

OpenStudy (anonymous):

yes i got36

OpenStudy (anonymous):

38

myininaya (myininaya):

2+6 isn't that big

OpenStudy (anonymous):

dont you have to multiply each term by 2?

myininaya (myininaya):

is it 2i+6i^2?

OpenStudy (anonymous):

and what about the square root?

OpenStudy (anonymous):

yes

myininaya (myininaya):

if so only the i is being multiplied by 2 and only i^2 is being multiplied by 6?

myininaya (myininaya):

you mean square i don't see any square roots

OpenStudy (anonymous):

2 is the square root of 6i

myininaya (myininaya):

you have 2i+6i^2 plug in 1 for i like this 2(1)+6(1)^2 follow the order of operations wait what? 2 is not the square root of 6i that is impossible

OpenStudy (anonymous):

idk thats what is says

myininaya (myininaya):

a square root looks like this: |dw:1397164335753:dw| you are saying \[2=\sqrt{6i}\] i have no clue where you are getting that from

myininaya (myininaya):

2 does not equal square root of 6i

OpenStudy (anonymous):

|dw:1397164362969:dw|

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