what is the value of the summation ∑i=14(2i+6i2)?
the answer choices A. 180 B. 200 C. 220 D. 240
I'm really having trouble understanding your problem? Can you be more clear what your expression is?
the 4 is at the top of the huge E, under neath it it says i=1, next to it in parenthesis it says (2i + 61^2)
so you mean to say this: \[\sum_{i=1}^{4}(2i+6i^2)\]
yesss
you can use some formulas are you can just plug in and then add the terms either way for this one since there isn't many terms
evaluate the expression 2i+6i^2 for i=1 for i=2 for i=3 for i=4 then you will have four terms add them
have you plugged in 1 for i in the expression 2i+6i^2?
yes i got36
38
2+6 isn't that big
dont you have to multiply each term by 2?
is it 2i+6i^2?
and what about the square root?
yes
if so only the i is being multiplied by 2 and only i^2 is being multiplied by 6?
you mean square i don't see any square roots
2 is the square root of 6i
you have 2i+6i^2 plug in 1 for i like this 2(1)+6(1)^2 follow the order of operations wait what? 2 is not the square root of 6i that is impossible
idk thats what is says
a square root looks like this: |dw:1397164335753:dw| you are saying \[2=\sqrt{6i}\] i have no clue where you are getting that from
2 does not equal square root of 6i
|dw:1397164362969:dw|
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