Question

Find all solutions in the interval [0, 2π).

sin2x + sin x = 0

Answer 1

Use the fact that sin2x = 2sinxcosx first.

Then factor out sinx.

Nice fake pic btw :P

Answer 2

btw, is it \(sin(2x)\) or \(sin^2x\).. big difference

Answer 3

lol @agent0smith

Answer 4

Thanks. It's the best way to attract pervs and trick them into doing my work. Dueche.@agent0smith Nice name by the way. Agent Smith.

It's sin^2x. Sorry about that @Luigi0210

Answer 5

LOL thanks. Good luck getting help, calling people... whatever that is. Looks german.

Answer 6

If it's sin^2 x then just factor out sinx right now.

Answer 7

Right click pic => google images

Or just use a less completely obviously fake pic than that one, wouldn't set off red flags in the first place.

Answer 8

a. x = 0, π, 4π/3, 5π/3
b. x = 0, π, π/3, 2π/3
c. x = 0, π, 3π/2

Answer 9

those are my options

Answer 10

So... start by factoring out sinx...

Answer 11

@girlfromafrica is it possible if I can marry you?

Answer 12

It's a British Pakistanian

Answer 13

And I don't care if people know my pic is fake. I don't want the internet world to see my face. Darling @ShadowLegendX This face is fake. You wouldn't want it.

Answer 14

@ShadowLegendX she could be a dude lol

Answer 15

@A_Plus_Forever

Answer 16

i replied on chat

Answer 17

Lol I'm not a dude.

Answer 18

and how would we know that? lol

Answer 19

Fine...I will go marry the 60year old german man in English chat @adrynicoleb

Answer 20

sin^2 x + sin x = 0

sooo factor out a sinx and what do you get?? @girlfromafrica

Answer 21

Lol I don't care what you thing.

0. I get 0. @agent0smith

Answer 22

Think

Answer 23

Show me what you get. It can't just be 0.

Answer 24

1^2 + 0?

Answer 25

LOL I'm cool with that ;)

Answer 26

If I change my pic to hot girl with big boobs, would anyone answer my question i just posted? :3

Answer 27

Haha they would @sourwing

Answer 28

@girlfromafrica not quite

sin^2 x + sin x = 0

factor out sinx then you should get

sinx(sinx + 1) = 0

Answer 29

All sorts of pervs would message you being like: "heyyy babe. you got snapchat?" LOL @sourwing

Answer 30

No,....................... it has to be a big retriceAND big boobs

Answer 31

*big butt

Answer 32

Ohhhh okay. @agent0smith What's the next step?

Answer 33

yo i cant reply much over pm cuz my boyfriend will see might see

Answer 34

ok

Answer 35

@ElisaNeedsHelp Then stop talking to random strangers

Answer 36

She's not lol

Answer 37

@girlfromafrica then you set each equal to zero:

sinx(sinx + 1) = 0

sinx = 0 sinx + 1 = 0

You should hopefully be able to solve from here.

Answer 38

You guys know each other? Ooooo y'all are playing with fire. @A_Plus_Forever @ElisaNeedsHelp

Answer 39

She doesent want her bf getting mad that she's talking to another boy but she's just talking but he'll still get mad

Answer 40

Guys. I need help getting the answer. Please. Options:

a. x = 0, π, 4π/3, 5π/3
b. x = 0, π, π/3, 2π/3
c. x = 0, π, 3π/2

Answer 41

Boys get like that.

Answer 42

cuz its not just you its so many other messages i get and other ppl are really weird

Answer 43

Lol no kidding. @ElisaNeedsHelp

Answer 44

Puberty.

Answer 45

@girlfromafrica attempt to solve what I gave you.

sinx = 0 sinx + 1 = 0

Answer 46

so i have many weird boy messages Your one of the normal ones lol

Answer 47

preech bruttha @A_Plus_Forever

Answer 48

How? All I get is 0. 0 0 0 0 0. That's all I get. @agent0smith

Answer 49

Who wants long D?

Answer 50

\(~~~~~~~~~~~~~~~~~~~~~~~~~~\Huge{\color{red}{\heartsuit}\color{orange}{\bigstar}\color{yellow}{\heartsuit}\color{green}{\bigstar}\color{blue}{\heartsuit}\color{purple}{\bigstar}\color{hotpink}{\heartsuit}}\)\(\Huge\bf\color{#FF0000}W\color{#FF4900}e\color{#FF9200}l\color{#FFDB00}c\color{#FFff00}o\color{#B6ff00}m\color{#6Dff00}e\color{#24ff00}~\color{#00ff00}t\color{#00ff49}o\color{#00ff92}~\color{#00ffDB}O\color{#00ffff}p\color{#00DBff}e\color{#0092ff}n\color{#0049ff}D\color{#0000ff}a\color{#2400ff}t\color{#6D00ff}i\color{#B600ff}n\color{#FF00ff}g\)\(~~~~~~~~~~~~~~~~~~~~~~~~~~\Huge{\color{red}{\heartsuit}\color{orange}{\bigstar}\color{yellow}{\heartsuit}\color{green}{\bigstar}\color{blue}{\heartsuit}\color{purple}{\bigstar}\color{hotpink}{\heartsuit}}\)

Answer 51

lol jkjkjkjkjk

Answer 52

Stooooop. @A_Plus_Forever

Answer 53

Find your dream girl ;)

Answer 54

@girlfromafrica what do you mean you just get 0. Do you mean x=0?

sinx = 0 sinx + 1 = 0
^where does sinx=0?? ^you've made no attempt to solve this one.

Answer 55

lol @A_Plus_Forever dont get like the other guys plz you have a good shot with somebody

Answer 56

How can I solve something that = 0? @agent0smith

Answer 57

Lol Opendating

Answer 58

@girlfromafrica do you have any idea how to solve trigonometric equations?

What value(s) of x, will make sinx=0?

sinx + 1 = 0, for this one, first you have to subtract 1 from both sides.

sinx = -1

What values of x will make sinx = -1?

Use a unit circle. Or something. Do not just say "i get 0".

Answer 59

Lol yeah right I cant get a girlfriend for shizballs

Answer 60

Lol im sure thats not true you proved me your a really good person :) and the words you said show you are worth it for somebody

Answer 61

You will get a gf *wink wink*

Answer 62

So I'm getting x = 0, π/3, π, 5π/3 as the final answer @agent0smith

Answer 63

Did you guess that as your answer? Because you answered zero questions from my last post.

Answer 64

No I didn't guess. I'm just trying to finish my hw while doing this

Answer 65

Then if you didn't guess, explain HOW you got that answer.

Answer 66

So to solve

sin(x) = 0

Looks like that happens at 2 points on that unit circle....which 2 points are those?

Answer 67

The one on the wayleft and the one on the way right @johnweldon1993

Answer 68

Rewrite sin(2x) as 2sin(x)cos(x):

sin(x) + 2sin(x)cos(x) = 0

Factor out sin(x):

sin(x)[1 + 2cos(x)] = 0

Set each factor to equal zero:

sin(x) = 0
x = 0, π

1 + 2cos(x) = 0
2cos(x) = -1
cos(x) = -1/2
x = π/3, 5π/3

@agent0smith

Answer 69

That's not the same problem as we've been doing... you pointed out it was sin^2 x not sin2x.

Answer 70

Okay so....I was wrong. @agent0smith

Answer 71

It's actually sin2x

Answer 72

If you're able to solve that one, then you're able to solve this one.

Answer 73

@girlfromafrica correct...

"The one on the way left" is resembled by \(\pi\) and the one of the far right resembles \(2 \pi\) which is also = to 0...

o far we have 2 points...\(\pi\) and 0

Now...onto the second equation @agent0smith has given you above...

sin(x) + 1 = 0
subtract 1 from both sides of the equation

sin(x) = -1

Where does sin(x) = -1 on that unit circle?

Answer 74

Oh wow.

Answer 75

@girlfromafrica Wait...it's sin(2x)?? -_-

Answer 76

I'M SORRY

Answer 77

Am I working it out right though?

Answer 78

I don't think my answer is right.

Answer 79

Easy way to check:

plug the options into
sin2x + sin x = 0

and see which make the equation true.

I don't understand how you went from saying "I get 0" to... writing out a complete solution...

Answer 80

https://answers.yahoo.com/question/index?qid=20140124114101AAriB8J

one of those looks awfully familiar...