Question

Solve each of the following equations. Give exact answers.

a) 4x-3 = 7
b) 15x2+x-6 = 0
c) 3x2-8x-1 = 0

Answer 1

Do you have anymore information?

Answer 2

No that's it.. but its a topic on logarithm and exponential equation

Answer 3

Ok, let's do A.

4x - 3 = 7
4/4x - 3 = 7/4

First, tell me what is 7 divided by 4 (7/4)

Answer 4

7/4 = 1.75

Answer 5

BroTip: It's always better to leave it in fractional form

Answer 6

Yeah.. rather than solving it outright. It makes it a little easier my friend said to me as well

Answer 7

do you still need help ?

Answer 8

if not you should close this post

Answer 9

quadratic formula.
ax^2 + bx + c = 0.
x = [-b + sqrt(b^2 - 4ac)] / (2a) or x = [-b - sqrt(b^2 - 4ac)] / (2a).

Answer 10

where a, b and c are some constants (in short, some numbers which will not change), you will have.

Answer 11

3x^2 - 8x - 1 = 0
3(x^2 - (8/3)x) - 1 = 0
3(x - (8/6))^2 - 3(64/36) - 1 = 0
3(x - (8/6))^2 - 16/3 - 1 = 0
3(x - (8/6))^2 - 19/3 = 0
3(x - (8/6))^2 = 19/3
(x - (8/6))^2 = 19/9
x - (8/6) = sqrt(19/9) or = -sqrt(19/9)
x = sqrt(19/9) + (8/6) or x = -sqrt(19/9) + (8/6)
x = sqrt(19/9) + (4/3) or x = -sqrt(19/9) + (4/3)

Answer 12

3x^2 - 8x - 1 = 0
3x^2 + (-8x) + (-1) = 0
a = 3, b = -8 and c = -1

Answer 13

using quadratic formula.
x = [8 + sqrt((-8)^2 - 4(3)(-1))] / (2)(3) or x = [8 - sqrt((-8)^2 - 4(3)(-1))] / (2)(3)
x = [8 + sqrt(64 + 12)] / 6 or x = [8 - sqrt(64 + 12)] / 6
x = (8/6) + sqrt(76)/6 or x = (8/6) - sqrt(76/6)
x = (4/3) + [sqrt(4)sqrt(19)] / [(2)(3)] or x = (4/3) - [sqrt(4)sqrt(19)] / [(2)(3)]
x = (4/3) + [2sqrt(19)] / [(2)(3)] or x = (4/3) - [2sqrt(19)] / [(2)(3)]
x = (4/3) + sqrt(19)/3 or x = (4/3) - sqrt(19)/3
x = (4/3) + sqrt(19)/sqrt(9) or x = (4/3) - sqrt(19)/sqrt(9)
x = (4/3) + sqrt(19/9) or x = (4/3) - sqrt(19/9).