Question

how do you solve for t?
1*3.34*10^5 +(T-0)(4160) = 4160 (50-T)(9)

Answer 1

is the answer 0?

Answer 2

is the problem
\[ 1 \cdot 3.34 \cdot 10^5 +(T-0)(4160) = 4160\cdot 9\cdot (50-T) \]
?

Answer 3

yes

Answer 4

\[ 334000 +4160T = 1872000 - 37440 T \\
41600 T = 1538000 \\
T= 36.971
\]

Answer 5

ohh thanks

Answer 6

do you happen to know anything about physics because now im questioning the use of that equation for the problem?

Answer 7

@phi

Answer 8

1 kg of ice at 0° C is mixed with 9 kg of water at 50° C (The latent heat of ice is 3.34x105 J/kg and the specific heat capacity of water is 4160 J/kg). What is the resulting temperature?