Question

The perimeter of a rectangle is 80inches. If the length of the rectangle is five inches more than four times the width, find the dimensions.

Answer 1

uhm, I'm not totally sure I have it, but I'm pretty sure yhu would set it up the way it's worded.
80=5+4w or x. whatever variable yhu decide to use doesn't matter.

Answer 2

Can someone correct me if I'm wrong?

Answer 3

the perimeter of a rectangle formula is P= 2(l+w)

Answer 4

P = 2w + 2l

L = 4W + 5

looks like a system of equations

Answer 5

so you would just substitute what we know 'L' equals..and put that into the first equation for every 'l' we see

P = 2w + 2l

Perimeter = 80 btw...so

80 = 2w + 2l
will now become

80 = 2w + 2(4w + 5)

Distribute that 2

80 = 2w + 8w + 10

Subtract 10 from both sides of this equation

70 = 2w + 8w

combine like terms...

70 = 10w

Divide both sides by 10

w = 7



If we know w = 7 ...we can solve for l by plugging that into either equation we have

80 = 2w + 2l

80 = 2(7) + 2l

80 = 14 + 2l

64 = 2l

l = 32



Now is that correct?

We knew that

L = 4W + 5

If that is true lets plug in W and L


32 = 4(7) + 5

32 = 28 + 5

32 = 32

so yes it works out...

w = 7 and L = 32

Answer 6

Dang.

Answer 7

Lol it just looks like a bit of work...but it's not too bad :)

Answer 8

Haha, system of equations is my worst area. ;n ;

Answer 9

Well if you ever need help, message me @Ria23 :) I'll explain it out step by step like I did here :D

Answer 10

I have a question that I need answered, it's median-median line, do yhu think yhu might be able to help me?