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Mathematics 13 Online
OpenStudy (anonymous):

Let's start off easy :) trig help???

OpenStudy (anonymous):

pi/18

OpenStudy (anonymous):

i messed up my equation let me reqrite

OpenStudy (anonymous):

\[\Huge \cos3x= -\frac{ 1 }{ 2 }\]

OpenStudy (anonymous):

sorry

OpenStudy (anonymous):

2pi/9

OpenStudy (anonymous):

\Huge Also Solve , [0,2pi)

OpenStudy (anonymous):

can you please explain why its that?

OpenStudy (anonymous):

2pi/9 = -(1/2)???

OpenStudy (anonymous):

(3)*2pi/9 =-1/2 you were looking for x and you had cos(3x) so yeah

OpenStudy (anonymous):

o wow i understand -.-

OpenStudy (anonymous):

u meant i shoud move cos to the other side.

OpenStudy (anonymous):

boom... cos-(1/2) = 3x

OpenStudy (anonymous):

\[\huge\frac{ 2\pi }{ 3 } * \frac{ 1 }{ 3 } = x\]

OpenStudy (anonymous):

is that what you meant?

OpenStudy (anonymous):

no because you have to take the inverse of cosine because cosine of 1/2 is not the same as cos(3x) memorize the unit circle because it makes calc a lot easier. you need to look for where cosine would be -1/2 which is at 2pi/3 and to solve for x from there you just need to divide 2pi/3 by 3

OpenStudy (anonymous):

I'm sorry if this isn't making perfect sense but its been 4 years since I took precalc and I'm not sure how to word it other than "well that's the way it is"

OpenStudy (anonymous):

i got x = 2pi/9 though lol

OpenStudy (anonymous):

hmm

OpenStudy (anonymous):

let me c

OpenStudy (anonymous):

that is right though

OpenStudy (anonymous):

peachy we did the same thing....................................................

OpenStudy (anonymous):

-____________________-

OpenStudy (anonymous):

we just worded it differently

OpenStudy (anonymous):

but cosine of -1/2 is .87758 so when you wrote what you did I didn't follow your steps

OpenStudy (anonymous):

"boom... cos-(1/2) = 3x" cuz this doesn't make sense

OpenStudy (anonymous):

I don't understand now why did you go into decimals? o-o

OpenStudy (anonymous):

ahhhh i shifted the cos from cos3x to the other side.^^^

OpenStudy (anonymous):

yeah math won't let you do that directly

OpenStudy (anonymous):

so it became 3x = cos -(1/2) from cos3x -(1/2)

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

thats where we differ because the only way to do that is to take the inverse of cosine do you know what that is?

OpenStudy (anonymous):

no please explain :D

OpenStudy (anonymous):

cos(0)=1 so the inverse of cosine (or cos^-1(x) cos^-1(1) = 0

OpenStudy (anonymous):

its just a way of flipping them

OpenStudy (anonymous):

oh i get it

OpenStudy (anonymous):

now how did u apply it to this equation again?

OpenStudy (anonymous):

so to solve this youre going to wanna take the inverse cosine of -1/2

OpenStudy (anonymous):

mhm

OpenStudy (anonymous):

and when you look at the unit circle which i linked above you can see that cosine = -1/2 when cos(2pi/3) do you follow me so far

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

inverse cosine of -1/2 is 120 = 2pi/3

OpenStudy (anonymous):

you need to solve so 3x = 2pi/3 now

OpenStudy (anonymous):

oh ok i seee ittt

OpenStudy (anonymous):

to fit the equation you were given and then 2pi/9

OpenStudy (anonymous):

divide by 3 3on both sides then we're golden

OpenStudy (anonymous):

so you followed all of that?

OpenStudy (anonymous):

yep thank you

OpenStudy (anonymous):

feel free to message me for more help! sorry I took so long explaining =/

OpenStudy (anonymous):

its fine you helped a lot.

OpenStudy (anonymous):

\[\Huge \sin2x+sinx = 0\]

OpenStudy (anonymous):

how would i go about solving this within [0,2pi)

OpenStudy (anonymous):

sin2x = 2sinxcosx

OpenStudy (anonymous):

yep so set that equal to -sin(x)

OpenStudy (anonymous):

2sincosx = -sinx???

OpenStudy (anonymous):

yes maam

OpenStudy (anonymous):

divide a sin over

OpenStudy (anonymous):

awesome thanks

OpenStudy (anonymous):

then easy peasy from there right?

OpenStudy (anonymous):

when i do identities and solving I always feel like i dont know it and am stuck but then someone tells me and im like OHHHHHHHHHHH i just dont remember the identity unless someone helps me recall it

OpenStudy (anonymous):

snxcosx=1

OpenStudy (anonymous):

make flashcards for identities it helps

OpenStudy (anonymous):

wait am i right?

OpenStudy (anonymous):

do i like square both sides or something

OpenStudy (anonymous):

wait for the problem we were working on

OpenStudy (anonymous):

yep we're now at sinxcosx = 1

OpenStudy (anonymous):

no we had 2*sin(x)*cos(x)=-sin(x)

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

i wrote something wrong mb

OpenStudy (anonymous):

i forgive you ;)

OpenStudy (anonymous):

divide a sin over and we get 2cos(x)=-1

OpenStudy (anonymous):

then cos(x)=-1/2

OpenStudy (anonymous):

cosx = -1/2

OpenStudy (anonymous):

girl why do you still have a sin there |dw:1397440087760:dw|

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